Source code for rx.linq.observable.start

from rx.core import Observable
from rx.internal import extensionclassmethod


@extensionclassmethod(Observable)
def start(cls, func, scheduler=None):
    """Invokes the specified function asynchronously on the specified
    scheduler, surfacing the result through an observable sequence.

    Example:
    res = rx.Observable.start(lambda: pprint('hello'))
    res = rx.Observable.start(lambda: pprint('hello'), rx.Scheduler.timeout)

    Keyword arguments:
    func -- {Function} Function to run asynchronously.
    scheduler -- {Scheduler} [Optional] Scheduler to run the function on. If
        not specified, defaults to Scheduler.timeout.

    Returns {Observable} An observable sequence exposing the function's
    result value, or an exception.

    Remarks:
    The function is called immediately, not during the subscription of the
    resulting sequence. Multiple subscriptions to the resulting sequence can
    observe the function's result.
    """

    return Observable.to_async(func, scheduler)()